Integrand size = 24, antiderivative size = 24 \[ \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\frac {x^{1+m} (a+b \text {arcsinh}(c x))}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac {(3-m) x^{1+m} (a+b \text {arcsinh}(c x))}{8 d^3 \left (1+c^2 x^2\right )}-\frac {b c (3-m) x^{2+m} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {2+m}{2},\frac {4+m}{2},-c^2 x^2\right )}{8 d^3 (2+m)}-\frac {b c x^{2+m} \operatorname {Hypergeometric2F1}\left (\frac {5}{2},\frac {2+m}{2},\frac {4+m}{2},-c^2 x^2\right )}{4 d^3 (2+m)}+\frac {(1-m) (3-m) \text {Int}\left (\frac {x^m (a+b \text {arcsinh}(c x))}{d+c^2 d x^2},x\right )}{8 d^2} \]
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Not integrable
Time = 0.19 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {x^{1+m} (a+b \text {arcsinh}(c x))}{4 d^3 \left (1+c^2 x^2\right )^2}-\frac {(b c) \int \frac {x^{1+m}}{\left (1+c^2 x^2\right )^{5/2}} \, dx}{4 d^3}+\frac {(3-m) \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^2} \, dx}{4 d} \\ & = \frac {x^{1+m} (a+b \text {arcsinh}(c x))}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac {(3-m) x^{1+m} (a+b \text {arcsinh}(c x))}{8 d^3 \left (1+c^2 x^2\right )}-\frac {b c x^{2+m} \operatorname {Hypergeometric2F1}\left (\frac {5}{2},\frac {2+m}{2},\frac {4+m}{2},-c^2 x^2\right )}{4 d^3 (2+m)}-\frac {(b c (3-m)) \int \frac {x^{1+m}}{\left (1+c^2 x^2\right )^{3/2}} \, dx}{8 d^3}+\frac {((1-m) (3-m)) \int \frac {x^m (a+b \text {arcsinh}(c x))}{d+c^2 d x^2} \, dx}{8 d^2} \\ & = \frac {x^{1+m} (a+b \text {arcsinh}(c x))}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac {(3-m) x^{1+m} (a+b \text {arcsinh}(c x))}{8 d^3 \left (1+c^2 x^2\right )}-\frac {b c (3-m) x^{2+m} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {2+m}{2},\frac {4+m}{2},-c^2 x^2\right )}{8 d^3 (2+m)}-\frac {b c x^{2+m} \operatorname {Hypergeometric2F1}\left (\frac {5}{2},\frac {2+m}{2},\frac {4+m}{2},-c^2 x^2\right )}{4 d^3 (2+m)}+\frac {((1-m) (3-m)) \int \frac {x^m (a+b \text {arcsinh}(c x))}{d+c^2 d x^2} \, dx}{8 d^2} \\ \end{align*}
Not integrable
Time = 5.24 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx \]
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Not integrable
Time = 0.29 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00
\[\int \frac {x^{m} \left (a +b \,\operatorname {arcsinh}\left (c x \right )\right )}{\left (c^{2} d \,x^{2}+d \right )^{3}}d x\]
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Not integrable
Time = 0.28 (sec) , antiderivative size = 52, normalized size of antiderivative = 2.17 \[ \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int { \frac {{\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} x^{m}}{{\left (c^{2} d x^{2} + d\right )}^{3}} \,d x } \]
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Not integrable
Time = 117.92 (sec) , antiderivative size = 71, normalized size of antiderivative = 2.96 \[ \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\frac {\int \frac {a x^{m}}{c^{6} x^{6} + 3 c^{4} x^{4} + 3 c^{2} x^{2} + 1}\, dx + \int \frac {b x^{m} \operatorname {asinh}{\left (c x \right )}}{c^{6} x^{6} + 3 c^{4} x^{4} + 3 c^{2} x^{2} + 1}\, dx}{d^{3}} \]
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Not integrable
Time = 0.28 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int { \frac {{\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} x^{m}}{{\left (c^{2} d x^{2} + d\right )}^{3}} \,d x } \]
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Not integrable
Time = 0.29 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int { \frac {{\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} x^{m}}{{\left (c^{2} d x^{2} + d\right )}^{3}} \,d x } \]
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Not integrable
Time = 2.71 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {x^m (a+b \text {arcsinh}(c x))}{\left (d+c^2 d x^2\right )^3} \, dx=\int \frac {x^m\,\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}{{\left (d\,c^2\,x^2+d\right )}^3} \,d x \]
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